Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (waleed_imtiaz):

In a set of pencils, 65% have red color rings,55% have green color rings,while 25% have both. THe pencils containing rings of neither red nor green are 45. the total number of pencils in the set : A) 900 1200 C) 1225 D) 1500 @Ganpat .......? u there ?

OpenStudy (waleed_imtiaz):

I have made another reason,. I dont know its correct or not...... CHeck this out....@Ganpat

OpenStudy (waleed_imtiaz):

OpenStudy (ganpat):

i am not sure, what exactly u intent to ask.. well, you have answer now, so you tilt that any how u like.. But to approach to 900.. Venn diagram itself would be sufficient.. and use that Union Formula.. A U B = A + B + A N B... (N means intersection)...

OpenStudy (waleed_imtiaz):

Okay..... THanks...

OpenStudy (ganpat):

so u understood , how we approached.. right ??

OpenStudy (waleed_imtiaz):

yes. I got ur point last night.. And I found another way to solve this problem. SO I was just sharing my calculation that I made... And I wasn't intend to ask anything....... I just wanted U to look on my calculation and coment.... :)

OpenStudy (ganpat):

well, you started you solution assuming answer as 900, right ??

OpenStudy (waleed_imtiaz):

yes.... Because I knew that was the right answer and according to my calculation... 900 only satisfies the whole problem ..... and If u try the same method for others. it willn't work or satisfy the given data in question...

OpenStudy (ganpat):

yes.. thats the point.. if you try with random approach, it will be time consuming right ?? say u start with 1500, it doesnt work, than 1200... and at last 900..

OpenStudy (waleed_imtiaz):

yes..... I know.. U are rite.... It will be time consuming then... SO I found another easy way..... very shortcut..... in 10-20 seconds...... CAn I share that also ?

OpenStudy (ganpat):

ohh please..

OpenStudy (waleed_imtiaz):

OpenStudy (ganpat):

awesome dude.. thats damn good.. amazing !!!!!!!!

OpenStudy (waleed_imtiaz):

thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!