The length of a rectangle is 4 cm more than twice the width. the perimeter is 80 cm. Find the dimensions of the rectangle

Question

ajprincess · Answer

Perimeter=2(l+w)
where l-length and w-width
l=w+4
P=2(w+4+w)
80=2(2w+4)
80/2=2w+4
40=2w+4
solve for w.
Then substitute the value of w in l=w+4 to find l.
Can u do?

anonymous · Answer

So L equals 22, w= 18 and the area would be 396?

ajprincess · Answer

ya

anonymous · Answer

okay how about -1/4(-36+12x)=?

anonymous · Answer

one fourth btw, not -1 divided by 4...

ajprincess · Answer

you mean ur question is 1/4(-36+12x)=?

anonymous · Answer

yeaaa!

jiteshmeghwal9 · Answer

first of all use distributive property to solve denominator first:)

anonymous · Answer

okay. so what would that be?

jiteshmeghwal9 · Answer

$$\frac{1}{-144+48x}$$

anonymous · Answer

huh? im sooo confused.

anonymous · Answer

ohhh nevermind. so you did -4 and distributed it to -36 and +12x

jiteshmeghwal9 · Answer

don't u know distributive property ???????

anonymous · Answer

yessss

jiteshmeghwal9 · Answer

so i use distributive property to solve denominator means i distribute 4 btw -36+12x

jiteshmeghwal9 · Answer

gt it @maherman97 ??????

anonymous · Answer

yeahh i know i figured that out. so then what?

jiteshmeghwal9 · Answer

so now it must be ur answer becoz it can't be solved further:)

anonymous · Answer

or is that simplest form? ohh okay thanks man

jiteshmeghwal9 · Answer

yw:)
Anytime