Question

Evaluate b^2c^-1 for b = -4 and c = 2.

is it -8

Answer 1

There is minus mistake:

\[(-4)^2 \times \frac{1}{2} = 16 \times \frac{1}{2} = ??\]

Answer 2

plug the given values in the expression.:)

Answer 3

oh.. 8

Answer 4

c^-1=1/c
so: b^2c^-1 = b^2/c = 16/2

Answer 5

Yes now you are right..

Answer 6

\[\large (-a)^2 = a^2\]

Answer 7

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