Question

Geometry, please help!

Answer 1

If cot x=1/2, what is the value of y?

Answer 2

well since x=1/2 and cos is adj/hyp then the hypo=6

Answer 3

if the hypo =6 \[3^{2}+(4y)^{2}=36\]
\[9+(4y)^{2}= 36\]
\[(4y)^{2}=25\]

Answer 4

4y=5
y=5/4

Answer 5

got it?

Answer 6

Yep:) Thanks!