Question

log3^x + log3^5 = 2 how can i solve this?

Answer 1

log3^x + log3^5 = 2
\[\log_3(5x) = 2\]
Use \(log_a(b)=c ~~~~~~<-->~~~~~~a^c=b\)

\[3^2=5x\]
Solve

Answer 2

so do i multiply 3 by 5

Answer 3

\[3^2=5x\]
Do the exponent first, then divide by 5
\[9=5x\]
\[x=\frac{9}{5}\]