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Mathematics 22 Online
OpenStudy (anonymous):

y = ax^2 + bx + c, Determine the solution set of 0 = ax^2 + bx + c. is it {0, 4}?

OpenStudy (lgbasallote):

how?

OpenStudy (anonymous):

Ø

OpenStudy (anonymous):

can you help me solve it??/

OpenStudy (anonymous):

@lgbasallote

OpenStudy (neo92):

this is a quadratic eqn therefore it have any two real or imaginary roots(solutions) de[ending on a,b,c

OpenStudy (anonymous):

soo...

OpenStudy (neo92):

soo i think the solution set is the set of complex numbers..

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