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Mathematics 18 Online
OpenStudy (anonymous):

Prove that: \[\frac{\cos3A-cosA}{\sin3A-sinA}+\frac{\cos2A-\cos4A}{\sin4A-\sin2A}=\frac{sinA}{\cos2Acos3A}\]

OpenStudy (experimentx):

first of all simplify using sin C - Sin D formula

OpenStudy (anonymous):

what math is this?

OpenStudy (experimentx):

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