Question

What is the problem with my void function?

I started it like

scanf...
then printf the character
the format is correct but what the hell is the problem?

Answer 1

Pls show us your whole code of void function.

Answer 2

I somehow changed it.
void askuser()
{ char p;
gotoxy(5,10);
printf("Do you want to continue?");
gotoxy(5,11);
printf("<Y//N>");
gotoxy(5,12);
scanf("%c",&p);
gotoxy(5,13);
printf("%c",p);
}

Answer 3

I think you are having problem with gotoxy() function, make sure if you included its library in the header.

Answer 4

No the gotoxy is fine it has its own function

Answer 5

Any unexpected behavior ?

Answer 6

When the part the scanf must play it only says Press any key to continue thus skipping the printing the character scanned part.

Answer 7

But when i compile without gotoXY, it compiles and runs as you say in my g++. Pls tell what you want to do ?

Answer 8

I just want to know why does my program stops at the scanf?

Answer 9

Which compiler ? I don't think it should stop.

Answer 10

Of course it stops in scanf, because scanf means "wait the user to enter something from the keyboard".

Answer 11

LOL i didn't noticed scanf, totally forgot it. @ktobah is right. It'll wait till you put any char for input.

Answer 12

No it totally stopped. I expected for it to wait for an input but it said Press any key to continue...

Answer 13

Tell me please, which library you include so your compiler reconize : gotoxy() ?

Answer 14

I suspect that gotoXY is moving the location of input stream, hence it reading char automatically at 5,10 location on screen, Thus, not letting you to type anything.

Answer 15

I found that it's in <conio.h> but it isn't standard so please don't use it, if not required.

Answer 16

I used conio.h, but the compiler didn't recognize it !!!

Answer 17

#include<conio.h>???

Answer 18

it depends on the compiler I think

Answer 19

I did that yes, and yes I think it depends on the compiler, I'm using Dev-C++, and I commented the portion of gotoxy on your code and I tried it and it works well.

Answer 20

You, so which compiler you have ?

Answer 21

Can we go back to my question why does it stop when it came upon the scanf????

Answer 22

Well i found this one http://stackoverflow.com/questions/7955145/which-header-file-i-need-to-include-to-use-gotoxy-function

Answer 23

void gotoxy(int x, int y)
{
static HANDLE h = NULL;
if(!h)
h = GetStdHandle(STD_OUTPUT_HANDLE);
COORD c = { x, y };
SetConsoleCursorPosition(h,c);
}

Answer 24

void gotoxy(int x, int y)
{
COORD coord;
coord.X = x;
coord.Y = y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), coord);
}

Answer 25

what is the difference between the two????

Answer 26

I tried with this code :
void gotoxy(int x, int y)
{
static HANDLE h = NULL;
if(!h)
h = GetStdHandle(STD_OUTPUT_HANDLE);
COORD c = { x, y };
SetConsoleCursorPosition(h,c);
}

inside your program and it works well.

Answer 27

Nothing. Both are same.

Answer 28

How suppose am I to solve my problem regarding the input of the variables???

Answer 29

I suggest that before defining your void function "askuser", first define gotoxy(), just copy and paste this code there then try to recompile your program and run it, then see the result.

Answer 30

its stops in the scanf part

Answer 31

Can you show me your main program (the code) ?

Answer 32

May I show you the whole code its my project xD

Answer 33

no no, I just wanted to see how you call your void function inside your main program. Look I tried this code and it works :

#include<stdio.h>
#include<windows.h>

void gotoxy(int x, int y)
{
static HANDLE h = NULL;
if(!h)
h = GetStdHandle(STD_OUTPUT_HANDLE);
COORD c = { x, y };
SetConsoleCursorPosition(h,c);
}

void askuser()
{ char p;
gotoxy(5,10);
printf("Do you want to continue?");
gotoxy(5,11);
printf("<Y//N>");
gotoxy(5,12);
scanf("%c",&p);
gotoxy(5,13);
printf("%c",p);
}

int main(){
askuser();
}

Answer 34

what is your compiler???

Answer 35

I'm using Dev-C++

Answer 36

really???
does it work???
xD thanks

Answer 37

haha yes, it works, did it work for you ?

Answer 38

I have not tried it yet

Answer 39

Ah ok, good luck then.

Answer 40

Can you teach me pointers?

Answer 41

Ops sorry @LemuelPogi I really have a research to complete also I'm not that good in pointers. Excuse me!

Answer 42

okey thanks for the help.

Answer 43

Ah You're welcome.