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If Logx (1 / 8) = - 3 / 2, then x is equal to
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is that read is \[\huge \log_x \left(\frac 18 \right) = -\frac 32\]
is that the question?
\[\log_{x}8^{-1} =-3/2\] \[-\log_{x}8=-3/2 \]
\[\log_{x}8=3/2\] \[x^{3/2}=8\] \[x^{3/2}=2^3\] \[x^{1/2}=2\] \[x=\sqrt{2}\]
u can see here http://www.wolframalpha.com/input/?i=Logx+%281+%2F+8%29+%3D+-+3+%2F+2%2C+then+x+
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