A fighter plane horizontally at an altitude of 1.5 Km with speed of 720 Km/h passes directly overhead an anticraft gun. At what angle from the vertical should the gun be fired from the shell with speed of 400m/s to hit the plane in shortest time?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (jfraser):
@ what angle should the shell be fired so that it reaches an altitude of 1500m? This is a fairly simple projectile question
OpenStudy (anonymous):
u see the plane is too moving
OpenStudy (anonymous):
@JFraser
OpenStudy (across):
I assume the shell is fired the moment the plane is immediately above the gun?
OpenStudy (ujjwal):
Speed of plane= 200m/s
let time be t
Therefore
200\(\times\) t=ucos\(\theta\)\(\times\) t
or, 200\(\times\) t=400cos\(\theta\) \(\times\)t
or, \(\theta\)=60 drgree
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ujjwal):
*degree
OpenStudy (anonymous):
but @ujjwal the answer in my book is 30 degree
OpenStudy (ujjwal):
that is equal to 30 degree to vertical.
OpenStudy (ujjwal):
I used angle with horizontal
OpenStudy (anonymous):
yes u r correct
Still Need Help?
Join the QuestionCove community and study together with friends!