A fighter plane horizontally at an altitude of 1.5 Km with speed of 720 Km/h passes directly overhead an anticraft gun. At what angle from the vertical should the gun be fired from the shell with speed of 400m/s to hit the plane in shortest time?
@ what angle should the shell be fired so that it reaches an altitude of 1500m? This is a fairly simple projectile question
u see the plane is too moving
@JFraser
I assume the shell is fired the moment the plane is immediately above the gun?
Speed of plane= 200m/s let time be t Therefore 200\(\times\) t=ucos\(\theta\)\(\times\) t or, 200\(\times\) t=400cos\(\theta\) \(\times\)t or, \(\theta\)=60 drgree
*degree
but @ujjwal the answer in my book is 30 degree
that is equal to 30 degree to vertical.
I used angle with horizontal
yes u r correct
thxxx
WC
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