The length of an equilateral triangle is the same as the length of a rectangle and the width of the rectangle is 2 inches less than its length. If the perimeter of the triangle is 4 inches less than the perimeter of the rectangle, what are the dimensions of the rectangle?
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OpenStudy (anonymous):
I would like to do it using algebra
OpenStudy (ajprincess):
Let the length of the triangle be x.
So the perimeter of the triangle=3x
Let the width of the rectangle=y
y=x-2
Perimeter of the rectangle=2(x+y)
=2(x+x-2)
=2(2x-2)
=4x-4
3x=4x-8
Can u find x nw?
OpenStudy (anonymous):
3x=4x-8
+8
Then it would become:
8+3x=4x
-3x -3x
Then it would be:
8=x
OpenStudy (anonymous):
Is that correct?
OpenStudy (ajprincess):
yeah u r right.:)
Nw find y.
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OpenStudy (ajprincess):
Can u?
OpenStudy (anonymous):
I would have to use y=x-2?
OpenStudy (anonymous):
right?
OpenStudy (ajprincess):
ya
OpenStudy (anonymous):
y=x-2
-x=-x
So it would be:
-x+y=-2
I don't think that is right :/
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OpenStudy (ajprincess):
y=8-2
nw can u?
OpenStudy (anonymous):
subtract 8-2=6
y=6
OpenStudy (anonymous):
I'm sure that's right
OpenStudy (ajprincess):
nw u hav the dimensions of the rectangle.
OpenStudy (anonymous):
Thank you so much.
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