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what is the domain of h(x)= 1/(4x^2 -21x -18)
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Domain will not include the numbers where \(4x^2 - 21x - 18 = 0\), as you don't ever have a 0 in the denominator. Got it?
is the answer.. (negative infinity, 6) u (6, infinity) ?
Let me check.
We have another root: \[-{3 \over 4} \]
so (-infinity, -3/4) u (-3/4, 6) u (6, infinity) ?
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