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Solve. 2x2 + 13x = –20
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ok lemme give you a brief intro. to quadratic equation : \[\large{ax^2+bx+c=0}\] -> general form of a quadratic equation
what do you think is the above equation , a quadratic equation?
Yes
ok good , so remember that the roots of a quadratic equation are : \[\large{roots =\frac{-b\pm \sqrt{b^2-4ac}}{2a}}\]
put b = 13 , a = 2 and c = 20
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I'm not sure
ok .. see solve this now : \[\large{\frac{-13\pm \sqrt{169-160}}{4}}\] \[\large{\frac{-13\pm \sqrt{9}}{4}}\]
x= 1/3 and x=3?
-10/4 = -5/2 and -16/4 = -4
sqrt{9}=3
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Ohhh. Wait okay I see what I did wrong. Thank you!
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