Question

Find three consecutive even integers whose sum is 114.

Answer 1

x,x+1,x+2

x+(x+1)+(x+2)=144
3x+3=144
3x=144/3=48
x=48/3=16

Answer 2

so x=16

Answer 3

Isn't it 3 consecutive integers?

Answer 4

yes. x 1st , x+1 2nd , x+3 3rd

Answer 5

so , it is 16, 16+1, 16+3?
16, 17, 19

Answer 6

no 16,16+1,16+2

Answer 7

that is 16,17&18

Answer 8

But their sum does not equal 114

Answer 9

sorry that is x+2 3rd

Answer 10

Everytime I use x+2 on my third, I get 16, 17, 19 and they aren't consecutive and their sum doesn't add to 114

Answer 11

sorry i have some mistake in calculation

Answer 12

x+(x+1)+(x+2)=144
3x+3=144
3x=144-3=141
x=141/3=47

Answer 13

37, 38 ,39

Answer 14

sum has to be 114 not 144 though

Answer 15

3x+3=114
3x=114-3=111
x=111/3=37

Answer 16

now cleared

Answer 17

YES! I HAD IT RIGHT!!!

Answer 18

i have many careless mistake saorry for that

Answer 19

It's alright, I make them too