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Mathematics 16 Online
OpenStudy (anonymous):

x2-18x+45

OpenStudy (jiteshmeghwal9):

first break the middle term such that the sum of the digits become -18x & product becomes 45x^2

OpenStudy (jiteshmeghwal9):

\[\LARGE{x^2-18x+45}\]\[\LARGE{x^2-15x-3x+45}\]\[\LARGE{x(x-15)-3(x-15)}\]\[\LARGE{(x-3)(x-15)}\]

OpenStudy (jiteshmeghwal9):

gt it @broderick365 ????

OpenStudy (anonymous):

is tHAT THE ANSWER

OpenStudy (jiteshmeghwal9):

yes!

OpenStudy (anonymous):

THANKSSS SO MUCH GOT MORE COMING

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