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Simplify the expression 3/a^-9 b A. 27a/b B. 3/ab^-8 C. 3a^9/b
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\[\LARGE{{3}\over{\frac{1}{a}}^{9b}}\]
thats not the answer. this is the problem
thats the expression
3 a^9 b a = 0 b = 0 integral_(-L)^L integral_(-L)^L 3 a^9 b db da = 0
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yes i found the ans
got it is c
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