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Find the missing measures. Given: ABC is a right triangle. BC = 5, AC = 20, AB = ?
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use the pythagoras theorem AC^2 = AB^2 + BC^2 plug in values of BC and AC and solve for AB
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18 sqrtof 2?
wait no it would be 5 sqrt 13
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20^2 = 5^2 + AB^2 AB^2 = 400 - 25 = 375 AB = sqrt375
375 = 3*5*5*5 = 15 *25
sqrt375 = 15sqrt5
sorry its 5 sqrt15 !!!
my bad logic.. sqrt 375 = sqrt25 * sqrt 15 = 5 * sqrt15
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agreed?
agreed!
lol - good!
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