Question

help

Answer 1

9 over h with an exponent of -3

Answer 2

??????????????????????????????????????????????

Answer 3

to make the exponent positive, flip the n in the denominator and make it in the numerator

Answer 4

so

\[\Large \frac{9}{h^{-3}}\]

becomes

\[\Large \frac{9h^3}{1}\]

which is the same as

\[\Large 9h^3\]

Answer 5

hint :
flip the denominator
like
x^ -3
do it 1/x^ -3

Answer 6

thx