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Mathematics 14 Online
OpenStudy (anonymous):

Find the number of solutions of –3x2 – 2x – 3 = 0.

OpenStudy (lgbasallote):

what is the degree of the equation?

OpenStudy (anonymous):

Find the number of solutions of –3x^2 – 2x – 3 = 0.

OpenStudy (lgbasallote):

so what do you think is the degree?

OpenStudy (anonymous):

second

OpenStudy (lgbasallote):

second degree...so the degree is 2 right?

OpenStudy (anonymous):

yes

OpenStudy (lgbasallote):

the number of solutions is then just equal to the degree

jimthompson5910 (jim_thompson5910):

well if you haven't learned about complex numbers yet, then there are no solutions (if you get complex numbers as your solutions)

Parth (parthkohli):

No real solutions, only complex. http://www.wolframalpha.com/input/?i=-3x%5E2+-+2x+-+3+%3D+0

OpenStudy (lgbasallote):

well the question was just "number of solutions".....

jimthompson5910 (jim_thompson5910):

true, but in most classes I've seen, complex numbers aren't learned until later So if the discriminant is negative, then you simply say "no real solutions" and you leave it at that.

OpenStudy (lgbasallote):

i still think it's just asking "number of solutions" regardless if it's real or not...but let's ask anyway @alittlehaphazard what's your lesson

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