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Factorise fully (n^2 - a^2) - (n - a)^2
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u can write (n^2 - a^2) =(n-a)(n+a) next take (n-a) as common n proceed
\[n^2 - a^2 - (n-a)^2 \implies n^2- a^2 - (n^2 -2an + a^2) \implies n^2 - a^2 - n^2 + 2an - a^2\] does that help?
use formula (a2-b2)=(a+b)(a-b )
sai1234 - thanks that was simple! lgbasallote - sorry it was a bit confusing. thanks anyway!
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