Question

Five positive integers have a mean of 10, a median of 12 and only one mode, which is 12. What is the difference between the largest and smallest of these numbers?

Answer 1

Start by saying that either three of the numbers equal 12, or two of them equal 12 (because the mode is 12).

Answer 2

I was thinking of doing
(a+b+c+d+e)/5= 10
_,12,10,12,_ =50

Answer 3

a + b + c + d = 60 - 12
a+ b + c + d = 48

smallest can be 0 .. and largest can be 38.. to get a mean of 10...

so i guess 38 -0 = 38 ???