Question

Display the ASCII characters. (Implement in do-while loop) with functions

Answer 1

can you show me what code you have done

Answer 2

and is it in C or java

Answer 3

c

Answer 4

ok

Answer 5

help me please
T_T

Answer 6

ok give me a min

Answer 7

do you want to print all characters ?

Answer 8

yah
thats what our teachers said

Answer 9

T_T

Answer 10

#include<stdio.h>
#include<conio.h>
void main()
{
char c=0;
while(c<255)
printf("\n%d ascii value is %c",c,c);
c=c+1;
}

Answer 11

its in while loop can you convert it in to do while() loop?

Answer 12

i dont know

Answer 13

T_T

Answer 14

ok

Answer 15

#include<stdio.h>
#include<conio.h>
void main()
{
char c=0;
do{
printf("\n%d ascii value is %c",c,c);
c=c+1;
}while(c<255);
getch();
}
//in function form:
#include<stdio.h>
#include<conio.h>
void ascii(void){ //function
char c=0;
do{
printf("\n%d ascii value is %c",c,c);
c=c+1;
}while(c<255);
}
void main()
{
ascii();
getch();
}

Answer 16

understand???

Answer 17

ill try it in turbo c

Answer 18

yes try it. if an problem occurs tell me ok :)

Answer 19

this one is the proper answer to your question program with function + do_while loop
//in function form:
#include<stdio.h>
#include<conio.h>
void ascii(void){ //function
char c=0;
do{
printf("\n%d ascii value is %c",c,c);
c=c+1;
}while(c<255);
}
void main()
{
ascii();
getch();
}

Answer 20

bro, their is an error occur constant out of range in comparison in function what to do?

Answer 21

in this part "while(c<255);"

Answer 22

ok lemme see

Answer 23

oh its not error its a warning. but its ok program is working accurately. warning is because 255 is a huge number no worries its ok

Answer 24

your right i tryied lesser value it works..

Answer 25

thanks a lot bro got many more problems.. T___T

Answer 26

mention not i like to help :)

Answer 27

ill post it