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Mathematics 20 Online
OpenStudy (anonymous):

( (3x^3y^2)^3)^2)=

OpenStudy (anonymous):

(a^m)^n = a^m*n ( (3x^3y^2)^3)^2) (3x^3y^2)^6 (3x^)^6(3y^2)^6 n proceed using abov formula

OpenStudy (anonymous):

\[((3x^3y^2)^3)^2\] sai1234's Formula rewritten: \[(a^m)^n=a^{m \times n}\] Start with the outside exponent and work your way in.

OpenStudy (anonymous):

im lost

OpenStudy (anonymous):

pretend the 3x^3 y^2 in your question is the a in that 2nd formula. Starting with the outside, you'll multiply the 2 and 3 exponents: \[((3x^3 y^2)^3)^2 = (3x^3 y^2)^5\] Then put the 5 into each of the things inside the brackets: \[(3x^3y^2)^5=3^5 x^{15} y^{10}\]

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