plz help....The area of the batter's box on a major league baseball field is 24ft. The length of the batter's box is 2ft more than the width . Find the length and width of a rectangular batter's box
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OpenStudy (anonymous):
area =l *w
l = w+2
24 = (w+2) *w
\[24 = w ^{2} +2w\]
\[w ^{2} +2w-24 =0\]
\[w ^{2}+6w-4w-24 =0\]
\[w(w+6)-4(w+6) =0\]
(w-4)(w+6)=0
therefore w=4
or w=-6
but dimension cannot be -ve
so w=4 ft
so can you find length?
OpenStudy (anonymous):
I am stuck how do l find the length
OpenStudy (anonymous):
I've already told you: l = w+2
OpenStudy (anonymous):
o o my bad l get it hold on
OpenStudy (anonymous):
the length is 6 ft
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OpenStudy (anonymous):
hey l just google this site not sure how it works tho so is this a open or closed discussion
OpenStudy (anonymous):
its open
OpenStudy (anonymous):
ok so l can l ask you another question:)
OpenStudy (anonymous):
go ahead
OpenStudy (anonymous):
thanks
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OpenStudy (anonymous):
I'll be back in 10min
OpenStudy (anonymous):
|dw:1343943821069:dw|how can i determine the area of the figure using the generic units defined below ...........so the small box to the right says = 1 square unit