Question

(a-c)/(x-a)=m, solve for x

Answer 1

(a-c) = m(x-a)
a-c = mx - ma
a-c+ma = mx
(a-c+am)/m = x
(a/m-c/m+(am/m)) = x
a/m-c/m+a = x
(a-c)/m + a = x

Answer 2

Thank you very much! :)

Answer 3

np

Answer 4

can you help me with this one:
Write an equation to solve-
two buses leave Houston at the same time and travel in opposite directions. One bus averages 55mi/h and the other bus averages 45mi/h. When will they be 400 mi apart?

Answer 5

eif they leave from the same spot... this is distence = rate*time problem.
so we want 55*t + 45*t = 400
notice the first two terms are r*t so we know the final answer will be distence.
t(55+45) = 400
t(100) = 400
t = 400/100 = 4