Question

-1(2^-1)

A. -2^1 B. -2^-1 C. None of the above

Answer 1

\[\huge -1(2^{-1}) \implies -1(\frac{1}{2^1})\]
does that help?

Answer 2

how would i do \[-1(2^{-1}) / 2^{-3}\]

Answer 3

how would you normally do \[\huge \frac{2^{-1}}{2^{-3}}\]

Answer 4

2^(-1-(-3))