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Help please? :c Factor completely: 2x2 − 6x − 56 2(x − 7)(x + 4) (2x − 14)(x + 4) (x − 7)(2x + 8) Prime
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\[2x^2 − 6x − 56=2(x^2-3x-28)\] Does that helps? How can we go on?
its one with the 2 taken out
Thank you guys c':
\[2x ^{2}-14x+8x-56\] \[2x(x-7)+8(x-7)\] \[(2x+8)(x-7)\]
2(x-7)(x+4)
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@jeanelle417 recheck your answer it should be (2x+8)(x-7) which is equivalent to your third choice
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