solve for the asymptotes:

(y-1)^2/64 - (x+4)/49 = 1 ;

my answer is y = +/- 8/7(x+4) + 1, and they say its correct but what happens to the "64" you square?

Question

solve for the asymptotes:

(y-1)^2/64 - (x+4)/49 = 1 ;

my answer is y =  +/- 8/7(x+4) + 1, and they say its correct but what happens to the "64" you square?

anonymous · Answer

* (x+4)^2

anonymous · Answer

http://www.wolframalpha.com/input/?i=%28y-1%29^2%2F64+-+%28x%2B4%29%2F49+%3D+ yes ur ans is right

anonymous · Answer

@giovkast

amistre64 · Answer

the 64 and 49 are clues to the "box" in the center of the hyperbola

amistre64 · Answer

sqrt(64) is the distance from center to vertex, since its on the positive value

sqrt(79) is distance from center to the "missing" vortex if it had been an ellipse

amistre64 · Answer

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