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Mathematics 21 Online
OpenStudy (anonymous):

integrate (2x^3-1)^2(6x^2)

OpenStudy (lgbasallote):

let u = 2x^3 - 1 du = 6x^2 so therefore the integral just becomes \[\int u^2 du\] does that help?

OpenStudy (anonymous):

hey continue it dont stop u r on the right track

OpenStudy (lgbasallote):

that's already an easy integral...do you still need help?

OpenStudy (anonymous):

24x^8-24x^5+6x^2

OpenStudy (anonymous):

\[(2x^3-1)^2(6x^2\]

OpenStudy (amistre64):

i simple way is just to expand it all out into a single polynomial and integrate it term for term

OpenStudy (amistre64):

but if method is "defined", then lgbas is prolly best

OpenStudy (anonymous):

true so in this question you can say \[49 * 12x\]

OpenStudy (anonymous):

|dw:1344008290718:dw|that will dije you the answer that you are looking for

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