Jose is paying for a $2 drink using bills in his wallet. He has four $1 bills, two $5 bills, and two $10 bills. If he selects two bills at random, one at a time from his wallet, without replacement, what is the probability that he will choose two $1 bills to pay for the drink?
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Question

Jose is paying for a $2 drink using bills in his wallet. He has four $1 bills, two $5 bills, and two $10 bills. If he selects two bills at random, one at a time from his wallet, without replacement, what is the probability that he will choose two $1 bills to pay for the drink? 
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anonymous · Answer

4/8 * 3/7

anonymous · Answer

the $1 bills iare what's concerned here...4 out of 8 are $1...the first one he takes has a 1/2 shot at being a $1...the second has a 3/7 shot at being a We only care about the $1 bills...4 out of 8 are $1...the first one he takes has a 1/2 shot at being a $1...the second has a 3/7 shot at being a $1: 
so P = 1/2*3/7
 p =3/14