Question

How do you factor this?

Answer 1

\[x ^{2}-xy-30y ^{2}\]

Answer 2

try
(x-6y)(x+5y)

Answer 3

here's how:
x2-6xy +5xy-30y2
=x(x-6y) + 5y(x-6y)
=(x+5y)(x-6y)

Answer 4

x^2-6xy+5xy-30y^2=0
Take x as common form the first two terns and take 5y as common from the last two terms.......
x(X-6y)+5y(x-6y)=0
So (x-6y)=0 and (x+5y)=0