Question

how many number of ways in which each committee can be selected..8 people from a group of 12

Answer 1

More like choosing 8 from 12. Which makes \(12C8\).

Answer 2

12!/8!

Answer 3

\[12C8 = {12! \over (12 - 8)!8!} \]

Answer 4

Manage the rest, okay?

Answer 5

yes thank you!

Answer 6

but..wouldnt it be 12!/(12-8)!4!??

Answer 7

no

Answer 8

\[nPr=\frac{n!}{(n-r)!}\]
\[nCr = \frac{nPr}{r!}=\frac{\frac{n!}{(n-r)!}}{r!}\to\ \frac{n!}{(n-r)!\ r!}\]