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Solve the following quadratic equation by using the quadratic formula. 5x²+2x-7=0
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1st multiply coefficients if 1st n last terms ==5 *-7=-35 find products of -35 whose sum or difference=+2 -35=7 *-5 where 7-5=2 u can slplit 5x²+2x-7=0 as 5x²+7x-5x-7=0 x(5x+70-1(5x+7)=0 proceed nxt
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(5x+7)(x-1)=0 noe equate each term =0 to get x values
x= 7/5, 1
well done
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k thanks
just small - difference in x=7/5
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