Question

Solve the following quadratic equation by completing the square.
x²+6x-7=0

Answer 1

go to <a href=' http://www.mathway.com/answer.aspx?p=calg?p=xSMB33+6x-7SMB010?p=29?p=?p=?p=?p=?p=0?p=?p=0?p=?p=?p=CompleteSMB15theSMB15Square' target='_blank'><img src=' http://www.mathway.com/math_image.aspx?p=xSMB02ESMB032SMB02eSMB03+6x-7SMB010?p=95?p=22' border='0' style='vertical-align:middle' alt='Click Here to Complete the Square' /></a>

Answer 2

add 7 to both sides
\[x^2+6x=7\]take half of 6, which is 3, square it to get 9 and add to both sides, write
\[(x+3)^2=7+9=16\]take the square root, don't forget the \(\pm\) get
\[x+3=4\]or \[x+3=-4\] solve for \(x\)

Answer 3

x=1 or x= -7