Question

Find the domain and range, and the equation for the axis of symmetry in the following parabola.
y=(x-4)²+6

Answer 1

since \((x-4)^2\geq 0\) on account of it is a square you know
\[(x-4)^2+6\geq 6\]

Answer 2

tells you the range is \([6\infty)\)

Answer 3

ok