What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)?
(1 point)
a.(x – 2)2 + (y – (–5))2 = 25
b.(x – (–2))2 + (y – 10)2 = 241
c.(x – 2)2 + (y – (–5))2 = 241
d.(x – (–2))2 + (y – 10)2 = 25

Question

What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)?
 (1 point)
a.(x – 2)2 + (y – (–5))2 = 25
b.(x – (–2))2 + (y – 10)2 = 241
c.(x – 2)2 + (y – (–5))2 = 241
d.(x – (–2))2 + (y – 10)2 = 25

anonymous · Answer

first find radius of the circle

anonymous · Answer

U there?

jkbo · Answer

alright i need a little more help then that please

anonymous · Answer

did u find radius of the circle

jkbo · Answer

i need help with that

anonymous · Answer

use distance formula and calculate it
got it?

jkbo · Answer

iam sorry i got a test and i really need the answer and how to do it this is my last day of summer school