what points is in the solution set of y < x^2 - 4x + 3?
(2, -1)?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
simply substitute x = 2 and y = -1
-1 < (2)^2 - 4(-2) + 3
-1 < 4 + 8 + 3
-1 < 15
is this true? is -1 less than 15?
OpenStudy (anonymous):
-1 < 15 is right
OpenStudy (anonymous):
wait isnt it -16?
OpenStudy (lgbasallote):
4 +8 = 12
12 + 3 = 15
OpenStudy (anonymous):
-16<0 which is also true
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
anyway since it's true that -1 < 15
then you are right
OpenStudy (anonymous):
ok thanks.
OpenStudy (lgbasallote):
wait you're right...i made a mistake in my calculation
-1< (2)^2 - 4(2) + 3
-1 < 4 - 8 + 3
-1 < -1
this is not true so it's not a solution
OpenStudy (anonymous):
okay, so i got it wrong the first time yeah?
OpenStudy (anonymous):
if i did, i shall try again..
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
yes. you need to try another ordered pair
OpenStudy (anonymous):
okay, can you check my answer again after i show my work? thanks.
OpenStudy (lgbasallote):
sure
OpenStudy (anonymous):
i tried (-3, 0)
-3 < (0)2 - 4(0) + 3
=-6
OpenStudy (anonymous):
i think this is true, do you think so?>
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
-3 < (0)^2 - 4(0) + 3
-3 < 3
yes it is true
OpenStudy (lgbasallote):
however...
OpenStudy (lgbasallote):
you substituted it wrong
OpenStudy (lgbasallote):
should be 0 < (3)^2 - 4(3) + 3
0< 9 - 12 + 3
0 < 0
this is not true
OpenStudy (anonymous):
hmm, so its wrong again.. aish:( ok i'll try it again
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
go for it
OpenStudy (anonymous):
i tried (1, 0)
so 0 < (1)2 - 4(1) + 3
0 <1x2-4x1+3
=-1?
OpenStudy (lgbasallote):
it's not 1 x 2 it's 1^2 that means 1 x 1
OpenStudy (anonymous):
ooh oops sorry i'll try i tagin.
OpenStudy (anonymous):
again*
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
sure
OpenStudy (anonymous):
0 < 1^2 - 4(0) + 3
=-4?
OpenStudy (lgbasallote):
why did it suddenly become 4(0)?
OpenStudy (anonymous):
oh God. i get confused. so sorry! wwait.
OpenStudy (anonymous):
0 < 1^2 - 4(1) + 3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
right. what does that become then?
OpenStudy (anonymous):
0<0 false
OpenStudy (lgbasallote):
correct
OpenStudy (lgbasallote):
so find a different ordered pair
OpenStudy (anonymous):
i think (-3, 0) is right..
0 < (-3)2 - 4(-3) + 3
=-9, true.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
you're 1/3 right and 3/4 wrong hehe
you're 2/3 wrong because
1) 0 is NOT less than -9
2) (-3)^2 - 4(-3) + 3 is NOT equal to -9
you're 1/3 right because
0 < (-3)^2 - 4(-3) + 3
0 < 9 + 12 + 3
0 < 24
and this is true
OpenStudy (lgbasallote):
you're 1/3 right and 2/3 wrong*
my math was wrong in my first statement =))