Question

\[\begin{array}{cc} \text{Find} \; \mathcal L \lbrace B(t) \rbrace \; \text{where} B(t) &= \sin2t \quad 0 \pi \end{array}\]

Answer 1

i got something like \[\Large \left[\frac{-e^{-st} (s \sin(2t) + 2\cos (2t) )}{s^2+4} \right|_0^\pi\]
is that right?

Answer 2

@lgbasallote yes you are right !

Answer 3

YAY!!! >:)))

Answer 4

so what do i do now o.O

Answer 5

just apply the limits . sin will get zero and cos will get -1

Answer 6

i got \[\huge \frac{-2e^{-\pi s} + 2}{s^2 + 4}\]
??

Answer 7

great !!!!!
correct.

Answer 8

WOOHOO!!!! \m/