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What is the solution set of the following equation? 6x^2 = 13x + 5
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{-1/3, 5/2}? 2x + 5 = 0 2x = -5 x = -5/2 (-2.5) 3x - 1 = 0 3x = 1 x = 1/3
oopsuies
\[\implies 6x^2 -13x - 5 = 0\] \[\implies (3x+1)(2x-5)=0\]
seems you made a mistake with signs
yeah..sorry but seems like its right
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if i change the signs
yep..change the signs and you're right already
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