Question

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

Which of the following equations is used in the process of solving this problem?
3n2 + 5 = 116
3n2 + 3n + 3 = 116
3n2 + 6n + 5 = 116

Answer 1

let the smallest of the consecutive integers be 'x'. then
medium number=(x+1)
largest number=(x+2)
A/q,
\[(x)^2+(x+1)^2+(x+2)^2=?\]