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Mathematics 13 Online
OpenStudy (anonymous):

derive v=4x^3 -200x^2 +2400x I have derived it to v'=12x^2 -400x +2400 But now i need to solve for the value of x

OpenStudy (lgbasallote):

did they give a value of v and v'?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

but the book seems to think that the answer is 7.85 i have no clue how it got that

OpenStudy (lgbasallote):

what's the full question?

OpenStudy (anonymous):

uhhh, the question is hold on

OpenStudy (anonymous):

one sec

OpenStudy (anonymous):

The volume of an open box is given by the formula v(x)=x(60-2x)(40-2x) where x is the length in centimetres of a square cut out of each corner of a sheet of cardboard 60cm long and 40cm wide. a) find the possible values of x b) what value of x gives the max maximum volume give your answer to 2 decimal places C what is this maximum volume?

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