someone help me please ...
9x^2+4x+5=0
solve

Question

someone help me please ...
9x^2+4x+5=0 
solve

parthkohli · Answer

Okay. What method are you comfortable with?
Factoring?
Quadratic formula?

anonymous · Answer

whatever ... just solve it ...

parthkohli · Answer

Though, I'd suggest the formula here.$$x = {-b \pm \sqrt{b^2  - 4ac} \over 2a} $$

parthkohli · Answer

$$\implies x = {-4 \pm \sqrt{4^2 - 4(9)(5)} \over 2(9)} $$Can you solve it?

angela210793 · Answer

does lovebird know wht a,b,c are? O.o

parthkohli · Answer

Okay.. wait..
$9x^2 + 4x + 5 = 0$
a        b      c

parthkohli · Answer

$a$ is the coefficient of $x^2$.
$b$ is the coefficient of $x^1$
$c$ is the coefficient of $x^0$ or $1$.

anonymous · Answer

oh then what can i doo @ParthKohli : i like you ... thnx :D

parthkohli · Answer

Okay, so can you continue with that?
Thanks!

anonymous · Answer

noo i cant .... help me

anonymous · Answer

i suck at maths

parthkohli · Answer

Okay.$$x = {-4\pm \sqrt{4^2 - 4(9)(5)} \over 2(9)} $$$$x = {-4 \pm \sqrt{16 - 180} \over 18} $$$$x = {-4 \pm \sqrt{-164} \over 18} $$Before continuing, do you know what $\pm$ is?

anonymous · Answer

yes i know that