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OpenStudy (anonymous):
Solve the following quadratic equation using the quadratic formula. Which of the following expressions gives the numerators of the solutions? 10x^2 - 19x + 6 = 0 a = 10, b = -19, and c = 6. b^2 - 4ac = (-19)^2 - 4(10)(6) = 361 - 240 = 121 The square root of 121 is 11. The numerator is -(-19) ± 11. 19 ± 11?
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