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OpenStudy (anonymous):
OpenStudy (anonymous):
jus plug in?
ganeshie8 (ganeshie8):
P = 10 log(Pout/Pin)
P = 20
Pout = 12
Pin = ?
ganeshie8 (ganeshie8):
plugin the given values in equation, you need to solve for Pin right ?
OpenStudy (phi):
can you replace P and Pout with their values and write down the new equation?
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OpenStudy (anonymous):
yes i need to find the Pin.
OpenStudy (phi):
can you replace P and Pout with their values and write down the new equation?
OpenStudy (anonymous):
20 = 10 log(12/x)
OpenStudy (phi):
the next step is divide both sides by 10
OpenStudy (phi):
can you do that?
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OpenStudy (anonymous):
yea i think so.
OpenStudy (phi):
what do we get?
OpenStudy (anonymous):
2= idk LOL
OpenStudy (phi):
if you had (10*3)/10 you would get 30/10 = 3
or more simply (10*3)/10 = (10/10)*3 = 3
i.e. "cancel the 10's)
so for 10 log(12/x) divided by 10 do the same thing
OpenStudy (phi):
\[ \frac{10\cdot log(\frac{12}{x})}{10}= ? \]
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OpenStudy (anonymous):
log(12/x)?
OpenStudy (anonymous):
20=10 log 12/x
OpenStudy (anonymous):
2=log 12/x
taking anti log
10^2=12/x
100=12/x
x=12/100
OpenStudy (anonymous):
0.12?
OpenStudy (anonymous):
right
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