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Mathematics 23 Online
OpenStudy (anonymous):

How many different arrangements of the letters in the word SCHOOL are there? ~ I got 750 because SCHOOL has 6 letters, so therefore you find 6! .... which is 720 yet i got that wrong, what did i do wrong?~

ganeshie8 (ganeshie8):

check it has two OO

ganeshie8 (ganeshie8):

to account for them, you need to divide 6! by 2! total no. of arrangements are : 6!/2!

OpenStudy (anonymous):

do repeating letters make a difference?

ganeshie8 (ganeshie8):

yes, lets take a small example

ganeshie8 (ganeshie8):

A, B how many arrangements possible using above 2 letters ?

OpenStudy (anonymous):

two

ganeshie8 (ganeshie8):

thats right ! what are they AB BA right ?

OpenStudy (anonymous):

yes.

ganeshie8 (ganeshie8):

C, C how many arrangements possible using above 2 letters ?

OpenStudy (anonymous):

oooh, i seee! massive thanks, there one solution. :)

ganeshie8 (ganeshie8):

:D

ganeshie8 (ganeshie8):

you just divide the "total permutations(6!)" with "redundancy letters permutations(2!)" to get the unique arrangements

OpenStudy (anonymous):

thanks! :)

ganeshie8 (ganeshie8):

np..

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