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Solve x2 + 9x + 20 = 0. A.x = 2, x = 10 B.x = −2, x = −10 C.x = −5, x = −4 D.x = 5, x = 4
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please help :)
x=-5,x=-4 \[x ^{x}+9x+20=20\] \[(x+4)(x+5)=0\] It's factoring question.
factor the trinomial first :) its just like the problem we worked with first :)
thank you @j814wong
Your welcome
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after you factor, set the two binomials equal to zero and solve for x :D
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