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Sketch the direction field of the differential equation : dx/dt = 2t Your assistance is appreciated.
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I have a good idea, but I am not so sure how steep to make the slopes. Also is t on the x axis and x on the y axis?
|dw:1344119965700:dw|x' is only proportional to t when t=1/2, dx/dt=1 so that will be a line at a 45 degree angle with the x-axis this thing should only get steeper as we move to the right along t...
okay
|dw:1344120098961:dw|we can also see that at t=0, dx/dt=0 so that will be horizontal lines
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