Look at the rhombus ABCD. Maddox made the following table to prove that diagonal AC of rhombus ABCD bisects its angles.
Maddox made the following table to prove that diagonal AC of rhombus ABCD bisects its angles. Statements Justifications 1.ABCD is a Rhombus 1.Given 2. AB = BC = CD = DA 2. CPCTC 3. AC = AC 3.reflexive property 4. Triangle ABC is congruent to triangle ACD 4. SSS postulate 5. Angle BAC = angle DAC, angle BCA = angle DCA 5. definition of rhombus Which two justifications did Maddox interchange while making the table? Justification 2 and Justification 3 Justification 4 and Justification 5 Justification 3 and Justification 4 Justification 2 and Justification 5
I think it is the last one.
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