A fighter plane flying horizontally at an altitude of 2 Km at speed of 200m/s passes directly above the aniti-aircarftgun.what is the minimum muzzle speed and at which angle from the vertical it should be fired to hit?
have you figured out the problem in the Q ... i particularly hate literature part.
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just what does this mean? "minimum muzzle speed so that it will make a hit"
for the minimum speed, the shell hits the plane at the highest point in its trajectory
no ... this means your minimum height of the shell must be 2km
nop it should be max...........so that we can use u^2/2g = 2000
and what must be you min?
here min velcoity means the min velocity req to hit the plane
where would be the minimum height? so that i would touch the plane?
so..hw do u figure out that? we dont have any method to find min h
why don't we have ... ? we have ... let vertical component of the velocity = y and horizontal component be = x
sorry ... let it by |dw:1344130674394:dw| we will use x, y for other purposes.
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