Question

(a-5)(a-2)=28

Answer 1

1. expand the factors.
(a-5)(a-2)=28
a(a-2) -5(a-2) = 28
a^2 - 2a - 5a +10 = 28
a^2 - 7a + 10 = 28

2. subtract 28 from both sides
a^2 - 7a + 10 - 28 = 28 -28
a^2 - 7a - 18 = 0

3. factor the expression
a^2 - 7a - 18 = 0
a^2 +2a - 9a - 18 = 0 <- can you try to factor this first?

Answer 2

so .. . it would be a^2 -7a-18

Answer 3

Not really, you need to take out common factor to expand it. I split the middle term into two so that you can do the factorization easier by taking out the common factors

Answer 4

I still dont get it .

Answer 5

Hmm.. let me try a little for you..
a^2 +2a - 9a - 18 = 0
For the first two terms, take out a as the common factor.
a(a+2) - 9a - 18 = 0
Can you try to factor the last two terms?

Answer 6

nevermind, found the answer .

Answer 7

thanks for trying though :)

Answer 8

I.. think you need to learn how to do it... *sigh* Welcome though..

Answer 9

I tried and i finally got down to this . ( a-9)(a+2) so a could equal to 9 or -2

Answer 10

Yes!!!!

Answer 11

:D